2+28x+4.9x^2=0

Solution for 2+28x+4.9x^2=0 equation:

2+28x+4.9x^2=0

a = 4.9; b = 28; c = +2;
Δ = b2-4ac
Δ = 282-4·4.9·2
Δ = 744.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-\sqrt{744.8}}{2*4.9}=\frac{-28-\sqrt{744.8}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+\sqrt{744.8}}{2*4.9}=\frac{-28+\sqrt{744.8}}{9.8}
$